Question

he age of a father 10 years ago was thrice the age of his son. ten years hence the father's age will be twice that of his son. the ratio of their present ages is

Answer 1

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Answer 2

Answer:

Let the age of Father and son be x and 3x years respectively.

After Ten years,

Age of father = x + 10 years

Age of son = 3x + 10

According to Question now,

(3x + 10) + 10 = 2(x + 10) + 10

3x + 20 = 2(x + 20)

3x + 20 = 2x + 40

3x - 2x = 40 - 20

x = 20 years.

Therefore, Required ratio :

(3x + 10) : (x + 10)

3(20) + 10 : 20 + 10

60 + 10 : 30

70 : 30

7 : 3

Therefore, the required ratio is 7:3.