Math, asked by gfaugjdKe3723, 1 year ago

He age of father 10 years ago was thrice the age of his son. ten years hence, father's age will be twice that of his son. the ratio of their present ages is:

Answers

Answered by InfamousInferno
1
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Answered by ƦαíηвσωStαƦ
76

Aɴsʀ:

  • The ratio of their present age = 7:3

Gɪɴ:

  • The age of father 10 years ago was thrice the age of his son. ten years hence, father's age will be twice that of his son.

N T Fɪɴ:

  • The ratio of their present age = ?

Solution:

Let,

The present age of Father and son be y and 3y years respectively.

10 ʏʀs ɢ:

  • Present age of father = y + 10

  • Present age of son = 3y + 10

Aʀɪɴɢ ʜ ɢɪɴ ǫsɪɴ:

(3y + 10) + 10 = 2 × (y + 10) + 10

➦ 3y + 20 = 2 × (y + 20)

➦ 3y + 20 = 2y + 40

➦ 3y - 2y = 40 - 20

➦ y = 20

Hɴ:

  • y = 20 years

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Tʜʀғʀ:

➦ The required ratio = (3y + 10) : (y + 10)

➦ The required ratio = 3(20) + 10 : 20 + 10

➦ The required ratio = 60 + 10 : 30

➦ The required ratio = 70 : 30

➦ The required ratio = 7 : 3

Tʜs:

  • The ratio of their present age = 7:3

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