He amount of calcium oxide required to react completely with 852 g of p4o10 is :- (atomic mass of p = 31) (cao + p4o10 ca3(po4)2)
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balance the chemical equation first....
6cao + p4o10 -------->2ca3(po4)2
1mole of p4o10 require 6 moles of cap to react completely.
Now according to the question....
mole of p4o10 = given mass/ molecular mass
= 852/280
=3.04mol
1 mole of p4o10 require 6 mole of cao, so 3.04 mole of p4o10 will require = 3.04×6 moles of cao
= 18.24 moles of cao
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