Question

He bob of a simple pendulum executes simple harmonic motion in water with a period t , while the period of oscillation of the bob is t0 in air. Neglecting frictional force of water and given that the density of the bob is (4/3) x 1000 kg/m3. What relationship between t and t0 is true ? (1) t = t0 (2) t = t0/2

Answer 1

Answer:

g (effective) =m(bob) - m(water displace) /m(bob) *g

=(4/3*1000*V-1000*V)*g/4/3*1000V

=g/4

New time period t=2pi *root(L/g effective)

=2pi*root(L/g/4)=2(to)

Second option is cprrect

Explanation:

L=lenght of string

V=volume of bob

Byoncy Force will act in up direction

Byoncy force=wt of liquid displaced by bob