Question

he body weighs 22.42 g and has a volume 4.7cc . the possible error in the measurment of error is 0.01 and volume is 0.1 respectively. find the max error in density

Answer 1

Answer:

It is the correct answer.

Step-by-step explanation:

Hope this attachment helps you.

Answer 2

Answer:

Correct option is

B

2 %

m=22.42gm,Δm=0.01gm⇒

m

Δm

=

22.42

0.01

=

22.42

1

v=4.7cc,Δv=0.1cc⇒

v

Δv

=

4.7

0.1

=

4.7

1

density d=

v

m

⇒ error

d

Δd

=

m

Δm

−

v

Δv

max

m

d

Δd

∣

max

=

m

Δm

+

v

Δv

d

Δd

∣

max

×100%=(

m

Δm

+

v

Δv

)×100%

⇒

d

Δd

∣

max

×100%=

2242

1

×100%+

47

1

×100%

=2.17%

nearly 2%