he car started moving and got fixed acceleration.
At the end of second second distance traveled 8 m. Distance
Which the car reaches the end of the 5th seconds is ....
A. 20 m
B. 50 m
C. 80 m
D. 100 m
Answers
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Straight motion changes regularly.
₁x₁ / ₂x₂ = (v₁t₁ + 1/2 at₁²) / (v₂t₂ + 1/2 at₂²)
Suppose v₀ = 0!
₂x₂ = ₁x₁ (t₂ / t₁) ²
= (8 m) [5 s / (2 s)] ²
= 50 m
₁x₁ / ₂x₂ = (v₁t₁ + 1/2 at₁²) / (v₂t₂ + 1/2 at₂²)
Suppose v₀ = 0!
₂x₂ = ₁x₁ (t₂ / t₁) ²
= (8 m) [5 s / (2 s)] ²
= 50 m
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