Question

He density of 1.40 molal solution of acetic acid is 1.084g/ml. The molarity of solution will be:
1) 1.30 M
2) 1.40 M
3) 1.50 M
4) 1.60 M

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Answer 1

Suppose the volume of solution is 1000 ml.

1.02 gm of acetic acid in 1 ml of soln.

1020 gm in 1000 ml of soln.

Number ofr moles =2⋅05M×1 lit=2.05 mol

Mass of solute =n×M⋅wt=2.05×60=123 gm

Mass of solvent =1020−123=897 gm

Molality =

60

123

×

897

1000

=2.28 mol kg

−1