Question

he EMF of cell, Cd(s) / Cd 2+ (0.01M) ‖ Cu2+ (0.5M )/ Cu, is 0.79V. Determine
the standard reduction potential of Cd electrode, if the standard electrode potential
of copper is 0.34 V

Answer 1

Answer:

Given that:-

E 0ccell =−0.34V

Ec cell=0

[Cu 2+]=?

The emf of electrode when dipped in different cocentrated solution is given by Nernst equation.

Eccell =E 0cell + 20.059log[Cu 2+]

⇒0=0.34+ 20.059log[Cu 2+]

⇒log[Cu 2+]=−0.34×0.0295

⇒log[Cu 2+ ]=−11.52

⇒[Cu 2+]≈2.98×10 −12M