Math, asked by chitrasingh0683, 11 months ago

he following
Exercise 19.5
(Use ruler and compass only to construct each of the folle
triangles)
1. Construct a triangle ABC in which AB = 4.5 cm, BC = 3 cm and AC-
an
2. Construct a triangle ABC in which AB = 4.5 cm, ZA = 30°, and AC =2
3. Construct a triangle ABC in which BC = 4.4 cm, ZA = 75° and ZR
4. Construct a triangle ABC in which AB = 7 cm, BC = 6.5 cm and ZCAR-
5. Construct a right-angled triangle whose longest side is 5.6 cm and an
side is 3.2 cm.
6. Construct an equilateral triangle with one side 3.5 cm.
7. Construct an isosceles triangle with base BC = 6.2 cm and altitude -48
8. Construct an isosceles triangle with base BC = 5.8 cm and vertical angle
9. Construct an isosceles right-angled triangle whose hypotenuse is 7 cm
10. Construct an isosceles triangle with base 2.8 cm and vertical angle = 30
Construction Problems: A geometrical construction combines both
asoning and skill. When you are asked to construct a figure, it requires​

Answers

Answered by amitnrw
0

ΔABC is constructed in which AB = 4.5 cm, ∠A = 30°, and AC =2 cm

Step-by-step explanation:

Please post Question separately one by one

answering

Construct a triangle ABC in which AB = 4.5 cm, ZA = 30°, and AC =2

Step 1 :  Draw a line segment AB = 4.5  cm

Step 2 : Taking suitable width of compass & taking A as center , draw an arc intersecting AB at M

Step 3 : keeping compass width Same taking M as center , draw arc intersecting earlier drawn arc at N

Step 4 : Reducing compass width slightly & taking M as center draw an arc

Step 5 : keeping compass width same as in step 4 and taking N as center draw arc ,intersecting arc drawn in step 4 at O

Step 6 : Draw a ray starting from A and passing through O

Step 7 : Take a length of  2 cm from A on Ray drawn in step 6 and mark other end as C

Step 8 : join BC

ΔABC is constructed in which AB = 4.5 cm, ∠A = 30°, and AC =2 cm

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Answered by Anonymous
0

\huge\star\mathfrak\blue{{Answer:-}}

Construct a triangle ABC in which AB = 4.5 cm, ZA = 30°, and AC =2

Step 1 : Draw a line segment AB = 4.5 cm

Step 2 : Taking suitable width of compass & taking A as center , draw an arc intersecting AB at M

Step 3 : keeping compass width Same taking M as center , draw arc intersecting earlier drawn arc at N

Step 4 : Reducing compass width slightly & taking M as center draw an arc

Step 5 : keeping compass width same as in step 4 and taking N as center draw arc ,intersecting arc drawn in step 4 at O

Step 6 : Draw a ray starting from A and passing through O

Step 7 : Take a length of 2 cm from A on Ray drawn in step 6 and mark other end as C

Step 8 : join BC

ΔABC is constructed in which AB = 4.5 cm, ∠A = 30°, and AC =2 cm

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