He given
32.
Two cars travelling on a straight road cross a kilometer stone A at the same time with velocities 20ms and
10ms with constant accelerations of Ims and 2ms respectively. If they cross another kilometer stone B
at the same instant, the distance between A and B is:
1) 600m
2) 800m
3) 1000m
4) 1200m
on same escalator, now moving he is
Answers
Answer:
600m
Explanation:
S1=s2
uA=20m/s
uB=10m/s
aA=1m/s2
aB=2m/s2
uAt+1/2aAt^2=uBt+1/2aBt^2
20t+1/2*1*t^2=10t+1/2*2*t^2
on solving we get t=20s
substituting in uAt+1/2aAt^2 we get
20*20+1/2*1*20^2
400+1/2*400
=600m
Distance between A and B is: 600m
Explanation:
Let say both car take time t secs to reach from A to B
Using formula
S = ut + (1/2)at²
Car 1
u = 20 m/s
a = 1 m/s²
t = t
=> S = 20t + (1/2)(1)t²
=> S = 20t + t²/2
Car 2
u = 10 m/s
a = 2 m/s²
t = t
=> S = 10t + (1/2)(2)t²
=> S = 10t + t²
10t + t² = 20t + t²/2
=> t²/2 = 10t
=> t /2 = 10
=> t = 20
Putting t = 20
S = 10t + t² = 200 + 400 = 600
Distance covered by both car = 600 m
Hence distance between A and B is: 600m
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