He greatest angle of a cyclic quadrilateral abcd in which anglea=(2x1)o,b=(y+5)o,c=(2y+5)o and d=(4x+7)o is
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Step-by-step explanation:
In cyclic quardrilateral sum of opposite angle is 90°
angle A + angle C =(2*x+1) + (2*y+5)= 90°
angle B + angle D = (2*y+5) + (4*x+7)= 90°
on solving these equation we can say that the angle C is greater angle in the cyclic quardrilateral
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