HE GUYS I REQUEST YOU PLZ ANS ME THIS QUES
i am having my exam on 18 th
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Answer:
v = dx / dt ( slope of x-t graph )
V1 = 20 / 4
= 5 m/s
V2 = -20/4
= -5 m/s
impulse = ∆p = pf - pi
= mv2 - mv1
= m ( v2-v1)
= 1 ( -5- - 5)
= -10 kg m/s
| impulse | = | -10|
= 10 kg m / s
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