Question

he hcf of how many distinct pairs of factors of 18000 is 75?

Answer 1

18,000= 2×3×3×2×5×2×5×2×5

As we know H.C.F means that the greatest number which divides other two number completely.

But , factors of 75= 5×5×3

But, there are three 5 in the factor of 18,000.So, the two numbers whose H.C.F is 75 must have two 5 in each of the number.

So, there is no ordered pair ,in the factor of 18,000 whose HCF is 75.

Answer 2

The answer is 41.

And the solution provided here is completely incorrect