Question

he larger of the two supplementary angles exceeds the smaller by 18°. Find them.​

Answer 1

Answer:

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Answer 2

let one angle be x

then the second angle=x+18

sum of supplementary angles =180°

A.T.Q.

x+x+18=180

= 2x +18=180

= 2x=180-18

= 2x= 168°

= x= 168/2

= x= 84°

=x+18°= 84+18= 102°

therefore smaller angle =84°,

other angle= 102°

Hope it helps, thanks !