Question

he larger of two complementary angles exceeds the smaller by 18 find them

Answer 1

let the two larger suplet the two larger supplementary angle larger Angle B X and smaller Angle B Y we know that X + Y is equal to 180 equation number first 180 - 21 18 is equal to 18 1 18 - 18 is equal to 2 162 is equal to 2 Y Y is equal to 162 upon 2 is equality 81 put the value of Y question 3rd x is equal to 180 minus y x is equal to 180 - 81 x is equal to 99 the larger Angle B 81 and this Mayavi 99

Answer 2

Answer: 36° and 54°

Step-by-step explanation:

We know that the sum of complementary angles is 90°.

Let the smaller be x.

As the larger exceeds the smaller by 18, the larger becomes x + 18.

Taking their sum,

x + x + 18 = 90

2x + 18 = 90

2x = 90 - 18

2x = 72

x = 72 / 2

x = 36°

x + 18 = 36 + 18 = 54°

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