Question

he length of a rectangle is three times its width. It the perimeter of the rectangle is 96m, find the length and breadth of the rectangle.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Working out:

We are provided with the information that length is greater than breadth by some factor and also the perimeter is given. And we have to find the length and breadth of the rectangle.

Given:

• Length is 3 times the width.
• Perimeter of the rectangle = 96 m

Then of course, width is smaller in measure

So, Let:

• Let width of the rectangle be x
• Then, length of the rectangle be 3x

Perimeter of the rectangle = 2(Length + Breadth)

So, let's plug the given consider values:

⇛ Perimeter = 2(l + b)

⇛ 96 m = 2(3x + x)

⇛ 96 m = 2(4x)

⇛ 96 m = 8x

Flipping it,

⇛ 8x = 96 m

⇛ x = 12 m (width)

Then, length = 3x = 36 m

So, the length and breadth of the rectangle:

$\large{\boxed{ \bf{ \red{l = 36 \: m }\: \: \: and \: \: \red{\: b = 12 \: m}}}}$

And we are done !!

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