Question

he magnetic field strength at a distance of 6cm from a thin, straight wire is 0.00006 T. What is the current in the wire?

Answer 1

Given: B= 6× 10^-5

d = 6cm = 6 ×10^-2

u = 4π ×10^-7

I =?

B= uI/2πd

6×10^-5 = 4π×10^-7 ×I/ 2π×6×10^-2

6×10^-5×2π×6×10^-2/ 4π×10^-7 = I

By solving,

18 = I

Therefore the value of current is 18 Ampere

Hope it helped you dear friend