Question

He may is 24years older than her daughter dhamini. 6years ago, he made was thrice as old as dhamini. find their present ages?​

Answer 1

Answer:

Therefore, present age of Dhamini = 18 years.

Present age of Hema =x+24=18+24=42 years.

Step-by-step explanation:

Let the present age of Dhamini be 'x' years then we can make the following table:

Dhamini Hema

Present age x x+24

6 years ago x−6 (x+24)−6=x+24−6=x+18

But as given that 6 years ago Hema was thrice as old as Dhamini

∴ x+18=3(x−6)

x+18=3x−18

x−3x=−18−18

−2x=−36

x=18

Therefore present age of Dhamini =x=18 years

Present age of Hema =x+24=18+24=42 years.

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Answer 2

✬ Himay = 42 Years ✬

✬ Dhamini = 18 Years ✬

Step-by-step explanation:

Given:

• Himay is 24 years older than her daughter Dhamini.
• 6 years ago he was thrice as old as Dhamini.

To Find:

• What are the present ages of both ?

Solution: Let Himay's present age be x years and Dhamini's present age be y years. Therefore,

➼ Himay's age = 24 more than Dhamini's age

➼ x = (y + 24) years.

[ Now, six years ago their ages were ]

• Himay age = (x – 6) years
• Dhamini age = (y – 6) years.

A/q

• 6 years ago Himay was thrice as old as Dhamini.

$\implies{\rm }$ (x – 6) = 3(y – 6)

$\implies{\rm }$ y + 24 – 6 = 3y – 18

$\implies{\rm }$ y + 18 = 3y – 18

$\implies{\rm }$ 18 + 18 = 3y – y

$\implies{\rm }$ 36 = 2y

$\implies{\rm }$ 36/2 = y

$\implies{\rm }$ 18 = y

So, present ages of

➬ Dhamini is y = 18 years

➬ Himay is x = y + 24 = 18 + 24 = 42 years