Math, asked by cavin950, 11 months ago

He number of natural numbers less than 1000, in which no two digits are repeated is

Answers

Answered by virtuematane
1

Answer:

The number of natural numbers less than 1000, in which no two digits are repeated is:

738

Step-by-step explanation:

As there are a total of 999 natural numbers from 1 to 999.

Also, the number of natural numbers in which two digits are repeated is: 261

( since, such numbers are:

11,22,33,44,55,66,77,88,99---- which are 9 numbers

100,101,110,111,112,113,114,115,116,117,118,119,121,122,131,133,141,144,151,155,161,166,171,177,181,188,191,199---- which are 28 numbers.

200,202,211,212,220,221,222,223,224,225,226,227,228,229,232,233,242,244,252,255,262,266,272,277,282,288,292,299---- which are 28 numbers.

similarly we can write a set of 28 numbers between 300-399,400-499,500-599,....900-999  

Hence, the total number of such numbers are: 9+28×9=261 )

Hence, the number of natural numbers less than 1000, in which no two digits are repeated is:

999-261=738

Answered by sain06533
0

Answer:

738

Step-by-step explanation:

Numbers less than 1000 are one digit no., two digits numbers and three digits number.

No. of one digit number =9

No. of two digit number in which =9×9=81

no. two are repeated

(For one's place we have 9 choice for ten's place we have 9 choices (0 excluded) )

No. of three digit number in which No. two digit are repeated =9×9×8

=648

(For hundred place we have 9 choice (0 excluded) for ten's place we have 9 choices & or One's place we have 8 choices )

∴ Total number less than 1000 in which no. two digits are repeated are : =9+81+648

=738

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