. He performs the experiment for two different values of angle of incidence: ∠i = 30° and ∠i = 45°.
The set of values of the angle of refraction (∠r) and angle of emergence (∠e), he is likely to observe
in the two cases, are
(a) [∠r = 30°, ∠e = 20°] and [∠r = 45°, ∠e = 28°]
(b) [∠r = 20°, ∠e = 30°] and [∠r = 45°, ∠e = 28°]
(c) [∠r = 20°, ∠e = 30°] and [∠r = 28°, ∠e = 45°]
(d) [∠r = 30°, ∠e = 20°] and [∠r = 28°, ∠e = 45°]
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Here OA is the incident ray.
Given:
The angle of incidence for first surface (air-glass interface),
i=55
∘
The angle of incidence for second surface (air-glass interface),
r
2
=40
∘
r
1
and r
2
are alternate interior angles,
∴ ∠r
1
=∠r
2
=40
∘
So, the angle of refraction at first surface r
1
=40
∘
Since, the emergent ray is parallel to the incident ray, the angle of emergence must be equal to angle of incidence , i.e.,
∠θ=∠i=55
∘
Answer:
the angle of refraction r
1
=40
o
the angle of emergence θ=55
o
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