Math, asked by ashimgolder, 1 year ago

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product of two numbers is 192. If the difference between these two numbers is
4, what is the sum of these two numbers ?



Answers

Answered by abhishek123
4
let the numbers be a and b. therefore a*b=192 and a-b=4. now we know the formula that (a-b)^2+4*a*b=(a+b)^2. hence a+b= \sqrt{4*4+4*192}= \sqrt{4(4+192)}= \sqrt{4*196}=2*14=28
Answered by vinod04jangid
0

Answer:

The sum is 28.

Step-by-step explanation:

Given: Product of two numbers is 192 & difference between them is 4.

Let, x \& y be two numbers then,

xy=192 and x-y=4.

To find: x+y.

We know that, (x+y)^{2}=(x-y)^{2}+4xy.

Substituting values we get,

(x+y)^{2}=4^{2}+4(192)\\            \ =16+768\\=784

= > (x+y)=28.

Therefore the sum of these two numbers is 28.

#SPJ2

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