Question

he
product of two numbers is 192. If the difference between these two numbers is
4, what is the sum of these two numbers ?

Answer 1

let the numbers be a and b. therefore a*b=192 and a-b=4. now we know the formula that $(a-b)^2+4*a*b=(a+b)^2$. hence $a+b= \sqrt{4*4+4*192}= \sqrt{4(4+192)}= \sqrt{4*196}=2*14=28$

Answer 2

Answer:

The sum is 28.

Step-by-step explanation:

Given: Product of two numbers is 192 & difference between them is 4.

Let, $x \& y$ be two numbers then,

$xy=192$ and $x-y=4$.

To find: $x+y$.

We know that, $(x+y)^{2}=(x-y)^{2}+4xy$.

Substituting values we get,

$(x+y)^{2}=4^{2}+4(192)\\ \ =16+768\\=784$

$= > (x+y)=28$.

Therefore the sum of these two numbers is 28.

#SPJ2