he roots of the equation (b – c) x² + (c – a) x + (a – b) = 0 are equal, then
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here the roots are equal so
b²= 4ac
(c-a)²=4(b-c)(a-b)
c²-2ac+a²=4b-4c(a-b)
c²-2ac+a²=4ab-4b²-4ac+4cb
c²-2ac+4ac+a²=4ab-4b²+4cb
c²+2ac+a²-4ab+4b²-4cb is the answer
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