Math, asked by mss0144, 4 months ago

He/she who knows, let him speak

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Anonymous: Tumna goggle sa cheat kyu kiya

nahakswapnil311: ᴀᴄʜᴀ ᴛᴜᴍ ᴅᴜɴᴅʜ ᴋᴇ ᴅɪᴋʜᴀᴏ ɢᴏᴏɢʟᴇ sᴇ ᴍɪʟᴀ ᴛᴏʜ ᴍᴇʀᴇ ǫᴜᴇ ᴘᴇ ᴀɴsᴡᴇʀ ᴋʀ ᴅᴇɴᴀ

Anonymous: Toh Screen shot kaha sa lya xD

Anonymous: Tum bss cheater ho xD hehe

nahakswapnil311: ɴʜɪ ᴀɢᴀʀ ɢᴏᴏɢʟᴇ sᴡ ᴋɪʏᴀ ᴛᴏʜ ᴀᴀᴘ ᴅᴜɴᴅʜ ʟᴇ ᴅɪᴋʜᴀᴏ ɴᴀᴀ

Anonymous: Aab dekha aisa detta hai answer

Anonymous: Bhai aap bura na manao toh plz Kisi aur question par baat kar lo

Anonymous: Because abhi answer dena iseliya notification aya ga baar baar

Anonymous: Accha Sry

Anonymous: Its okay

Answers

Answered by Anonymous

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$\large \bf \red{Answer}$

$\tt \small{Let \: in = \int Cotn \: xdx}$

$\tt \small{ = \int \: cot^{n - 2 } x. \: cot^{2} \: x \: dx}$

$\tt \small{= \int \: cot^{n - 2} \: x. \: (cosec^{2} \: x - 1) \: dx }$

$\tt \small{ = \int \: cot^{n - 2} \: x. \: cosec^{2} \: x \: dx - \int \: cot^{n - 2} \: x \: dx \: }$

$\tt \small{ = - (cot^{ n- 2}x)/(n - 1) - 1 n - 2 + \: c }$

$\tt\small \bf{Which \: is \: the \: required \: reduction \: formula.}$

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Anonymous: Thanks for Mark brainlist

mss0144: ur wlcm

Anonymous: Hmmm

mss0144: r u boy or girl

Anonymous: Vaisa jaankar kya karoga ?

Anonymous: Btw...I am boy

mss0144: ok as u wish

Answered by UniqueBabe

answer is in attachment

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