He sides of a triangle are in the ratio of 1/2 : 1/3 : 1/4. If its perimeter is 52 cm, the length of the smallest side is: (a) 9 cm
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let the sides of the triangle be X/2 , X /3 and X / 4
according to the question :-
x/2 + x/3 + x/4 = 52
6x + 4x + 3x / 12 = 52
13x = 52×12
x = 52×12/13
x = 48
length of sides = X/2 = 48/2 = 24 cm
X/3 = 48/3 = 16 cm
X/4 = 48/4 = 12 cm
Hence the length of smallest side is 12 cm
CHECKING RESULTS :-
24+16+12 = 52
52 = 52
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