Question

he solid was created by connecting two congruent square pyramids to a rectangular prism.


A rectangular prism with a length of 14 inches, width of 15 inches, and height of 15 inches. 2 square pyramids with triangular sides with a height of 18 inches.



What is the surface area of this solid?



_____________ square inches

1380

1500

1920

3000

please answer quickly

Answer 1

SOLUTION

TO CHOOSE THE CORRECT OPTION

The solid was created by connecting two congruent square pyramids to a rectangular prism.

A rectangular prism with a length of 14 inches, width of 15 inches, and height of 15 inches. 2 square pyramids with triangular sides with a height of 18 inches.

The surface area of this solid ___ square inches

• 1380

• 1500

• 1920

• 3000

EVALUATION

Here it is given that the solid was created by connecting two congruent square pyramids to a rectangular prism

The rectangular prism consists of 4 rectangles

Each with length of 14 inches, width of 15 inches

Area of each rectangles

= 14 × 15 square inches

= 210 square inches

So area of the rectangular prism

= 4 × 210 square inches

= 840 square inches

Again square pyramids consists of 8 triangles

Each of base 15 inches and height 18 inches

Area of each triangle

$\displaystyle\sf{ = \frac{1}{2} \times 15 \times 18 \: \: \: square \: inches }$

$\displaystyle\sf{ = 9 \times 15 \: \: \: square \: inches }$

$\displaystyle\sf{ = 135 \: \: \: square \: inches }$

Area of square pyramids

= 8 × 135 square inches

= 1080 square inches

Hence the surface area of this solid

= ( 840 + 1080 ) square inches

= 1920 square inches

FINAL ANSWER

Hence the correct option is 1920

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