Question

he sum of 55 consecutive integers is 120.

What is the third number in this sequence?

Answer 1

Answer:

Step-by-step explanation:

sum of n consecutive integers=n/2(1st no.+last no.)=55/2(x+x+55)

=>55/2(2x+55)=120=>2x+55=120*2/55

=>2x=240/55-55=240-3025/55=-2785/55

=>x=-2785/110=(-25)(appx)

3rd no. is -25+3=-22

Hope it helps