He sum of three prime numbers is 100. If one of them exceeds another by 36, then one of the numbers is:
amitnrw:
x + x + 36 + 2 = 100 => 2x = 62 so x = 31 , x+36 = 67 so three prime numbers are 2 , 31 & 67
one number has to be 2 as for sum of 3 prime number to be even its necessary to have one even number which is also prime that is only 2.
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Step-by-step explanation: hey mate
Let p1+p2+p3=100, also let p2=p1+36⟹2p1+p3=64, from here p1≠p2≠2⟹p3=2, hence p1=31⟹p2=67.
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Answered by
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Answer:
Step-by-step explanation:
x + x + 36 + 2 = 100
=> 2x = 62
so x = 31 ,
x+36 = 67
so three prime numbers are 2 , 31 & 67
one number has to be 2 as for sum of 3 prime number to be even its necessary to have one even number which is also prime that is only 2.
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