Chemistry, asked by sumitgoswami9908, 11 months ago

He vapour pressure of pure benzene at 25c is 639.7 mm of hg and the vapour pressure of a solution of non-volatile solute in benzene at 25c is 631.9 mm hg. The molality of the solution is:

Answers

Answered by yenula
5

(p - p_{x} ) /p = n/N

(639.7 -631.9) / 639.7 = n/12.82

7.8/639.7 = n/12.82

n = (7.8 × 12.82) / 639.7

n = 99.99/ 639.7

n = 0.156

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