Question

He wavelength of a spectral line emitted by hydrogen atom in the lyman series is 16 / 15r cm. What is the value of n2? (where, r = rydberg constant)

Answer 1

Answer:

n2 =4 is the answerr please mark as brainlist

Answer 2

Answer:

The value of n₂ is 4.

Explanation:

The wavelength of hydrogen spectrum in the Lyman series is calculated as,

$\frac{1}{\lambda} =R(\frac{1}{1^2}- \frac{1}{n_2^2} )$        (1)

Where,

λ=wavelength of the hydrogen spectrum

R=rydberg constant

n₂=higher energy state

From the question, we have the value of wavelength and by substituting the value of wavelength in equation (1) we get;

$\frac{15R}{16} =R(\frac{1}{1^2}- \frac{1}{n_2^2} )$

$\frac{15}{16} =\frac{n_2^2-1}{n_2^2}$

$15n_2^2=16n_2^2-16$

$n_2^2=16$

$n_2=4$

So, the value of n₂ is 4.

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