Question

he
Zeroes
or
polynomialx²-√2x-12 are​

Answer 1

Answer:

Step-by-step explanation:

x²-√2x-12

$=x^{2}-3\sqrt{2}x +2\sqrt{2} x-12\\=x(x-3\sqrt{2})+2\sqrt{2}(x-3\sqrt{2})\\=(x-3\sqrt{2})(x+2\sqrt{2} )$

zeros of the polynomial = $3\sqrt{2} ,-2\sqrt{2}$