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PHYSICS
A capillary tube of radius r is immersed in water and water rises in it to a height h. The mass of water in the capillary tube is 5g. Another capillary tube of radius 2r is immersed in water. The mass of water that will rise in this tube is:
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ANSWER
Given : r
1
=r h
1
=h r
2
=2r
Using rh=constant
∴ r
2
h
2
=r
1
h
1
(2r)h
2
=rh ⟹h
2
=
2
h
Mass of the water in the capillary M=ρ(πr
2
h) where ρ is the density of the water
Given : Mass of water that rises in the first capillary M
1
=5 g
∴ 5=ρπr
2
h ............(1)
Mass of water that will rise in second capillary M
2
=ρ(πr
2
2
h
2
)
M
2
=ρπ(2r)
2
2
h
=2×ρπr
2
h
⟹ M
2
=2×5=10 g
hey mate here is your answer......
Limbs is the odd one out.
hope it will helpful for you........