heat applied to system = 100W , wprk done = 75 j find ∆u ?
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Applying Required Formula :
- ∆Q = 100 W = 100j / s
- ∆w = 75 j / s
[ ∆Q = ∆u - ∆w ]
- ∆u = ∆Q - ∆w
- ∆u = 100 - 75 J / s
• Value of ∆u = 25 J /S
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Answered by
1
By law of conservation of energy,
Total energy= Work done + Internal Energy
100=75+U=25 J/s
Hence, Internal energy is increasing at the rate of 25 W
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