Heat energy necessary to raise the temperatureof 5 Kgwater from 85 degree celsius to35 degree celsius is?
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Explanation:
For water, the value of . C is 4.186Jg°C.So,Q=750×4.186×85=266858J=266.858kJDT = temperature difference =100-20=80 0C. Answer is 266.858kj1 calorie = 4.18 Joules. Thus 4180 Joules of energy of heats required for a Kilogram of water through just one degree centigrade
Answered by
1
For water, the value of . C is 4.186Jg°C.So,Q=750×4.186×85=266858J=266.858kJDT = temperature difference =100-20=80 0C. Answer is 266.858kj1 calorie = 4.18 Joules.
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