Heat energy required to convert 500ml of water completely to vapour?
Answers
Given---
Volume of the Water = 500 ml
= 0.5 Liter.
Converting liter into m³,
1 m³ = 100 l
⇒ 0.5 l = 0.5/100 m³
= 0.005 m³
Density of the Water = 1000 kg/m³
Using the Formula,
Density = Mass/Volume
Mass = Density × Volume
Mass = 1000 × 0.005
= 5 kg.
Since, the Initial Temperature of the Water is not given. Thus, Let the Temperature of the Water be 100°C.
Using the Formula,
Amount of Heat energy Required = Mass × Latent heat of Vaporization.
⇒ Q = m × L
Latent heat of Vaporization of Water = 2260 J/kg.
⇒ Q = 5 × 2260
= 11300 J
Thus, the amount of Heat energy required to convert Water at 100° C into vapor is 11300 Joules.
If the Initial Temperature of the Water will be given, then You can calculate the Total heat as---
Amount of Heat energy required to bring the water from temperature t to 100 °C
= mass × Spec. Heat Capacity × Change in temperature.
= m × c × Δt
Thus, Total Heat = mcΔt + Q
By this formula, Total amount of heat can be easily calculated.