Heat flows from a reservoir at 800 k to another reservoir at 250 k. If entropy change of the hot reservoir is 4 kj/k, determine the entropy change of the cold reservoir
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Answer:
12.8kj/K
Explanation:
the hot reservoir loses an energy Q by heat that causes a change in its entropy
ΔSh= -Q/Th (1)
ΔSh=entropy of the hot reservoir
Th = temperature of the hot reservoir
the cold reservoir absorbs an amount of energy Q by heat released from the hot reservoir
ΔSc=Q/Tc (2)
ΔSc=entropy of the cold reservoir
Tc=temperature of the cold reservoir
by taking the ratio of equations 1 and 2,
4/ΔSc=250K/800K
ΔSc=4 x 800/250=12.8kj/K
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