Question

Heat flows through a wooden board 30 mm thick at 0.0086 W/cm3 when one of its sides is 20˚C warmer than the other. Determine the thermal conductivity of the wood.

Answer 1

The thermal conductivity of wood is 0.387 W/mK

Explanation:

We know that thermal conductivity is given by

$k=\frac{QL}{A\Delta T}$

Given the length of the two sides of the board L = 30 mm = 0.03 m

Heat flowing per sq cm of area = 0.0086 W/cm

Thus, Q/A = (0.086 ×3) W/cm² = (0.0086 × 10000 × 3) W/m² = 258 W/m²

Temperature difference ΔT = 20°C = 20 K

Thus, the thermal conductivity of the wood

$k=\frac{258\times 0.03}{20}$ W/mK

$\implies k=0.387$ W/mK

Hope this answer is  helpful.

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