Heat is being supplied at a constant rate to a
sphere of ice which is melting at the rate of
0.1 gm/sec. It melts completely in 100 sec. The
rate of rise of temperature thereafter will be
(Assume no loss of heat.)
(A) 0.8 °C/sec
(B) 5.4 °C/sec
(C) 3.6 °C/sec
(D) will change with time
Answers
Answered by
0
Answer:
Correct option is
A
0.8
0
C/sec
Rate of melting of ice is 0.1gmsec
−1
Total mass of ice m
ice
=0.1×100=10gms since all the ice melts in 100 secs.
Total amount of heat supplied to melt 10 gms of ice Q=10×80cal=800cal
Rate at which heat is supplied
dt
dQ
=
100
800
=8calsec
−1
After all the ice melts, the water temp will rise.
Rate of rise of temp of water
dt
dT
=
m
water
×s
water
dt
dQ
=
10×1
8
=0.8
0
Csec
−1
Similar questions