Question

Heat liberated when 100 ml of 1 n naoh is neutralized by 300 ml of 1n hcl is

Answer 1

The heat liberated will be 5.73 Kj

Explanation :

The reaction of hcl and naoh is as follows:

HCL + NAOH = H₂O + NACL

Hence 1 mole of HCL will react with 1 mole of naoh

=> 100 ml of 1 n hcl will react with 100 ml of 1 n naoh ( the rest 200 ml of hcl will be unused)

we know that Heat of neutralization of HCL and NAOH is 57.3 KJ/mole

i.e.

1000 ml of 1 n naoh will react with 1000 ml of 1 n hcl to give 57.3 kj of heat.

=> 100 ml of 1 n naoh will react with 100 ml of 1 n hcl to give

= 57.3 x 100/1000 = 5.73 KJ

Hence the heat liberated will be 5.73 Kj

Answer 2

Answer:

5.73kJ

Explanation:

100mL of 1NNaOH will be exactly neutralised with 100mL of 1NHCl.

1000mL of 1NNaOH react with 1000mL of HCl to give 57.3kJ of heat

∴100mL of 1NNaOH will react with 100mL of 1NHCl to give 57.31000×100=5.73kJ of heat.