Question

Heat of 30 kcal is supplied to a system and 4200 J of external work is done on the system so that its volume decreases at constant pressure.What is change in its internal energy ?

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Answer 1

Answer:-

∆Q = 30× 4200

= 126000 J

∆W = -4200 J

∆U = ∆Q - ∆W

= 126000 + 4200

1.302 × 10^5 J