Question

heat of 30kcal is supplied to a system and 4200J of external work is done on the system so that it's volume decreases at constant pressure. what is the change in internal energy.(J=4200 J/kcal)

plzzzzz answer this question......plzzzzzzzzzz

Answer 1

Answer:

hope....it...helps....

answer attached down as image'...

Explanation:

Answer 2

Change in internal energy is 130.2 KJ

Explanation:

Given,

Q = 30 kcal

Work done , W = 4200 joule

Let us first convert our heat to Joules,

Q = 30 kcal = $30 kcal\times \left ( \frac{4200\ J}{1 kcal }\right )$

We get,

Q = 126000 J

According to first law of dynamics,

$\Delta U = Q + W$

$\Delta U = 126000 + 4200$J

$\Delta U = 130200$ J

$\Delta U = 130.2$KJ

Change in internal energy is 130.2 KJ