Question

heat of combustion of benzoic acid at constant volume at 25 degree centigrade is - 32 33 kilo joule per mole and 0.5 grams of benzoic acid is burnt in bomb calorimeter the temperature of calorimeter increased by 0.53 degree centigrade in the same bomb calorimeter 1 gram of c 286 and then the temperature increased by 2.0 degree centigrade held held for combustion of c 286 is

Answer 1

For one mole combustion  1530  k^J/mol heat is required.

Explanation:

△H   for C6H5COOH = -3233\ k^J/mol

Moles in O Sy = 0.5 / 122    =   1 / 244   mol

Heat evaluated = ( 1 /  244   × 3233) kJ

get specific heat for bomb calanmeter be

5 × 0.53 o  =  3233 /  244  kJ

8 =  3233  / 244 × 0.53

= 25 kJ/ °C

When temp increases by 2.04  °C

Heat supplied =2.04 × 25 = 51 k J

Therefore 54 kJ is released when 1g C2H6 is burnt  i.e.  1 /  30 mol

For 1 mol, heat is 51 × 30  =  1530  k^J/mol

Hence for one mole combustion  1530  k^J/mol heat is required.

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Calculate amount of heat required to raise the temperature of 5 grams of iron from 25 degree centigrade to 75 degree centigrade the specific heat capacity of iron is 0.450 Joule per gram ?

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