Physics, asked by 959g, 1 year ago

Heat of vaporization: How much energy is needed to heat 1.0 kg of mercury metal from 10.0°C to its boiling point (357°C) and vaporize it completely? For mercury, C = 140 J/kg·°C and Hv = 3.06×105 J/kg.

Answers

Answered by Anonymous
3

Answer:

354580Joules is required to heat the mercury metal and burn it completely.

Explanation:

Given data

mercury = 1 gram

Temperature = 10.0°C to 357°C

C = 140 J/kg·°C

Hv = 3.06×10^5 J/kg.

To find

Energy required to hear mercury and vaporize it completely

Energy Required = Heat added for temperature during change in phase + Heat of vaporization.

= mass*Cp* Change in temperature

+ heat of Vaporization

= 1*140*(357-10) + 3.06×10^5 J/kg.

= 48580 + 3.06×10^5 J/kg.

=354580Joules

354580Joules is required to heat the mercury metal and burn it completely.

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