Heat released in neutralization reaction of 500ml of 1N Hcl and 500ml of 1N Nh4OH is 1.36 k calories. the heat of ionisation of nh4oh is
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Explanation:
Number of grams equivalent to HCL = 500 ×0.1 / 1000 = 0.05
Numbers of gram equivalent to Nh4OH = 500 × 0.2 /1000 = 0.1
Sodium hydroxide is completely neutrelized by HCL
1 gram equivalent of sodium hydroxide liberates 57.3 kj
gram equivalent of NaOH on neutrelization will liberates
= 0.1 ×57.3 / 1 = 5.73 kj
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