Question

Heat required to convent
1kg of ice at a loc to steam
(or) water vapour at 100c is?​

Answer 1

Answer:

Given

Mass - 1 Kg

Temp - 100 c

To find Heat required.

Q = m * L water .

Here L Water - Heat of vaporization.

When a material in liquid state is given energy, it changes its phase from liquid to vapor; the energy absorbed in this process is called heat of vaporization. The heat of vaporization of water is about 2,260 kJ/kg.

Q = 1 * 2260

Q = 2260 kJ/kg

Given

Mass - 1 Kg

Temp - 0 c

To find Heat required.

Q = m * L ice.

Here L Water - Latent heat of ice .

while ice melts, it remains at 0 °C (32 °F), and the liquid water that is formed with the latent heat of fusion is also at 0 °C. The heat of fusion for water at 0 °C is approximately 334 joules

Q = 1 * 334

Q = 334 kJ/kg

Thanks

Explanation: