Heat required to convert 2kg of ice at -10°c into steam at 100
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Answer:
HEAT REQUIRED TO CONVERT ICE FROM -10°C TO 0°C = ms(T2–T1)
= 2* 1/2 *(0+10) = 10 kcal
HEAT REQUIRED TO CONVERT ICE AT 0°C TO WATER AT 0°C = M L
= 2*80 = 160 kcal
HEAT REQUIRED TO CONVERT WATER AT 0°C TO WATER AT 100°C
= 2 * 1 * (100–0) = 200 kcal
HEAT REQUIRED TO CONVERT WATER AT 100°C TO STEAM AT 100°C
= 2 * 530 = 1060 kcal
TOTAL HEAT = 10 + 160 + 200 + 1060 kcal
= 1430 kcal
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