Question

Heat required to convert one gram of ice at 0oc into steam at 100o c is

Answer 1

✴️Hello....friend....✴️
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☛Here is your answer dear :---
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☛I͟c͟e͟----->W͟a͟t͟e͟r͟----->S͟t͟e͟a͟m͟

⚫First of all let's know the method of solving this problem....

Step 1st
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Convert 0°C of ice into 0°C of water.

Step 2nd
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Then convert 0°C of water into 100° C of water.

Step 3rd
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Now, convert 100°C of water into 100°C of steam.

☑️======>Now, let's solve this problem

◼️Heat required =
Q = M × L1 + M × S ( T2 - T1 ) + M × L2
Now,
◼️L1 = latent heat of fusion of water 334J/gm
====> 79.7 Cal/gm

◼️L2 = latent heat of vapourization of water 2258J/gm =====> 539.417 Cal/gm

S = Specific heat of water 4.186J/gm

☛Now,
Q = 1 × 334 + 1 × 4.186 × (100 - 0) + 1 + 2258
====> 3010.6J
______________or_____________
=====> 3010.6/4.186
=====> 719.206 Cal.

Hope it will help you!
Thanks!!☺️
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Answer 2

Answer:

716 cal (Answer)

• The amount of heat required to convert 1 g of ice at 0°C into steam at 100°C, is 716 cal.