Heat required to raise temperature of 1 kg of water from 20 degree C to 80degree C will be
Answers
Answered by
9
Answer:
60 k cal
Explanation:
Given :
Mass m = 1 kg
Temperature difference Δ T = 80 - 20 C
Δ T = 60 C
We know :
Specific heat capacity of water c = 4200 J / kg / C
We are asked to find Heat energy Q
We know :
Q = m c Δ T
Putting values here we get :
Q = 1 × 4200 × 60 J
Q = 252 × 10³ J
Q = 252 k J
In term of calorie :
Q = 252 / 4.2 k cal
Q = 60 k cal
Therefore , required Heat is 60 k cal.
Answered by
0
Answer:
252 j
Explanation:
Answer is correct
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