Question

Heat the water in one beaker to 90°c
and other to 60°C. Mix the water with
these beakers? What will be the temperature of mixtures​

Answer 1

By principle of calorimetry
Ms(90-t)=Ms(t-60)
90-t=t-60
150=2t
T=75

Answer 2

Given : Two different water solutions at 90°C and 60°C,

To find : Temperature of the mixture,

Solution :

Applying the concept of Calorimetry,

Considering the mass(m) and Specific heat(S) of both the quantities same, We apply the following formula,

⇒Ms($t_{1}$-t)=Ms(t-$t_{2}$),

⇒Ms(90-t)=Ms(t-60),

We get,

⇒90-t=t-60,

⇒2t=150,

t=75°C

The temperature of mixtures​ is t=75°C.