Question

Heater A has resistance 690,working voltage 230. Heater B has resistance 460, working voltage 230.Which heater require a fuse of higher anperage

Answer 1

Answer:

Heater B requires fuse of higher rating

Explanation:

GIVEN:

For Heater A:

Resistance R1 = 690 and Voltage V1 = 230V

For Heater B:

Resistance R2 = 460 and Voltage V2 = 230V

TO FIND: Which heater needs fuse of higher amperes?

SOLUTION:

Current through Heater A = I1

V = IR [Formula]

V1 = I1*R1

I1 = $\frac{V1}{R1}$= $\frac{230}{690}$ = 0.34A

Current through Heater B = I2

V = IR [Formula]

V2 = I2*R2

I2 = $\frac{V2}{R2}$= $\frac{230}{460}$ = 0.5A

Since, current through B is greater than current through A, thus Heater B requires fuse of higher rating

Hope it helps u :)