heater coil is rated 100 watt 220 volt it is cut into two identical parts fullstop both parts are connected together in parallel to the same square shots of 220 volt calculate the energy liberated per second in the new combination.
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Answer:The resistance of the one part is half of the full coil
R(initial)=484
R(final)=242
Now there are two resistance of resistance R(final)
Which we are put in parallel conn.
Now R(eq.)=121 ohm
Now energy liberated per sec. Is equal to the power P=v²/r
P=220*220/121
P=400watt
Hope this soln. Is helpul
Explanation:
kusum752000:
is this correct
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